50x^2-20x-6=0

Solution for 50x^2-20x-6=0 equation:

50x^2-20x-6=0

a = 50; b = -20; c = -6;
Δ = b2-4ac
Δ = -202-4·50·(-6)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*50}=\frac{-20}{100}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*50}=\frac{60}{100}
=3/5
$